See MathJax.
When a=0, there are two solutions to ax2+bx+c=0 and they are
x=2a−b±b2−4ac.
\begin{align}
\dot{x} & = \sigma(y-x) \\
\dot{y} & = \rho x - y - xz \\
\dot{z} & = -\beta z + xy
\end{align}
(k=1∑nakbk)2≤(k=1∑nak2)(k=1∑nbk2)
V1×V2=∣∣∣∣∣∣∣i∂u∂X∂v∂Xj∂u∂Y∂v∂Yk00∣∣∣∣∣∣∣
P(E)=(kn)pk(1−p)n−k
(ϕ5−ϕ)e52π1=1+1+1+1+1+…e−8πe−6πe−4πe−2π
1+(1−q)q2+(1−q)(1−q2)q6+⋯=j=0∏∞(1−q5j+2)(1−q5j+3)1,for ∣q∣<1.
\begin{align}
\nabla \times \vec{\mathbf{B}} -\, \frac1c\, \frac{\partial\vec{\mathbf{E}}}{\partial t} & = \frac{4\pi}{c}\vec{\mathbf{j}} \\
\nabla \cdot \vec{\mathbf{E}} & = 4 \pi \rho \\
\nabla \times \vec{\mathbf{E}}\, +\, \frac1c\, \frac{\partial\vec{\mathbf{B}}}{\partial t} & = \vec{\mathbf{0}} \\
\nabla \cdot \vec{\mathbf{B}} & = 0
\end{align}
Math